Cobrir $\mathbf{\frac{\textcolor{#ef4444}{2}}{\textcolor{#3b82f6}{3}}}$ da massa destacada é uma fração de uma quantidade: $\mathbf{\frac{\textcolor{#ef4444}{2}}{\textcolor{#3b82f6}{3}}}$ dos 9 quadrinhos destacados.

$\mathbf{\dfrac{\textcolor{#ef4444}{2}}{\textcolor{#3b82f6}{3}} \times \textcolor{#3b82f6}{9}}$

= $\mathbf{\dfrac{\textcolor{#ef4444}{18}}{\textcolor{#3b82f6}{3}}}$

= 6

São 6 quadrinhos. E isso confirma que $\mathbf{\frac{\textcolor{#ef4444}{2}}{\textcolor{#3b82f6}{3}}}$ de $\mathbf{\frac{\textcolor{#ef4444}{3}}{\textcolor{#3b82f6}{4}}}$ do tabuleiro é a metade dele, porque 6 de 12 é $\mathbf{\frac{\textcolor{#ef4444}{1}}{\textcolor{#3b82f6}{2}}}$ :

$\mathbf{\dfrac{\textcolor{#ef4444}{2}}{\textcolor{#3b82f6}{3}} \times \dfrac{\textcolor{#ef4444}{3}}{\textcolor{#3b82f6}{4}}}$

= $\mathbf{\dfrac{\textcolor{#ef4444}{6}}{\textcolor{#3b82f6}{12}}}$

= $\mathbf{\dfrac{\textcolor{#ef4444}{1}}{\textcolor{#3b82f6}{2}}}$

Como todos os quadrinhos destacados são iguais, qualquer 6 dos 9 servem.

Resposta correta: pintar exatamente 6 dos 9 quadrinhos destacados (2/3 dos 9).

Questão Q14924